MadSci Network: Biochemistry |

Posted By:

Date:

Area of science:

ID:

Hello Robin,

I'm a simple biochemist (not a physiologist) but here it goes anyway. If you assume that an average adult male is 60% (50% for women) water by weight and that the total fluid volume in a person is the sum total of all their intracellular fluid (ICF, 55% of total body water) and extracellular fluid (ECF, 45% of total body water) then it becomes possible to calculate how much sodium is in a person.

Sodium levels are usually reported in millimoles or milliequivalents, but for our purposes, milliequivalence is the same as millimolar (mM) because sodium has only +1 charge.

The concentration of sodium in intracellular fluid is low (10 mM) - therefore the weight of sodium in a 70 kg male is:

0.01 mol/l x 58.5g/mol Na x 70000g x 0.6 (%water) x 0.55 (%ICF) = 13.5g

A similar calculation for ECF where the concentration of sodium is about 145 mM would be:

0.145 mol/l x 58.5g/mol x 70000g x 0.6 x 0.45 (%ECF) = 160.32g

Therefore the total amount of sodium is about 173.82g

You can convert this to a number of sodium ions using the molecular weight and Avogadro's number:

173.82g / 58.5g/mole x 6.023 x 10^23 molecules/mole = **1.78 x 10^24 Na ions
**

**
**

Try the links in the MadSci Library for more information on Biochemistry.

MadSci Network

© 1997, Washington University Medical School

webadmin@www.madsci.org