MadSci Network: Chemistry |
Henry's Law is not going to help with this question. The concepts of Chemical Equilibrium are the most useful in this situation. Carbon dioxide (CO2) is soluble in H2O. About 90mL of CO2(gas=g) at 1atm will dissolve in 100mL of H2O at 20C and about 1% reacts to form carbonic acid (H2CO3) (ref 1) ~1% CO2(g) + H2O(l) --------> H2CO3 <------------------- ~99% The free gas (CO2) and water are normally favored over the acid. However, this is an equilibrium situation, not a chemical reaction that goes to completion. Modification of the conditions of the system can shift the equilibrium. For the case we're interested in, the volume of the system is fixed (such as a soda bottle) and an increase in the overall pressure (all gasses) would shift the equilibrium in favor of the acid. This is true as the release of more CO2 would further increase the pressure, and the equilibrium only allows for the overall pressure to go to some finite value, otherwise our soda bottles would spontaneously explode!! Or at least get uncomfortably pressurized. We can artificially push the equilibrium in favor of the acid by intentionally increasing the pressure of the system (soda bottle) with an air pump. By encouraging the formation of the carbonic acid we keep our previously opened drink from going flat. When the drink is opened again the acid we've kept in the liquid decomposes to H2O & CO2 and our drink remains pleasantly 'fizzy'. The operating principle is called Le Chatelier's Principle: When a disturbance is imposed on a system in equilibrium, the equilibrium shifts in such a way as to undo, in part, the effect of the disturbance. References: 1) B.H. Mahan, University Chemistry, 2nd ed, Adison Wesley, 1969. 2) F. Brescia, J. Arents, H. Meislich, A. Turk, Fundamentals of Chemistry A Modern Introduction, Academic Press, 1970. 3) J.V. Quagliano, L.M. Vallarino, Chemisrty, 3rd ed., Prentice Hall, 1969.
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