Subject: Moon escaping

In "nine planets" the Moon escape velocity is listed as 2.38 km/sec. 
And the moon is orbiting earth at 1.03 km/sec. It seem to me that it 
would matter which way you "leave" and this would change the Delta-v 
you would need to escape. Also since the Moon isn't perfect circle 
the Moon's speed will vary. Also I don't imagine it's taking into 
account the gravity of Earth. And also would the Earth/Moon orbit be 
a factor. How much do all these factors add up to to be? It also seem 
like you could go the "opposite" direction landing on the Moon, and 
thereby not need to deacelerate as much. 

So, the question is what is the minimal delta-v needed to leave the 
moon in order to get back to Earth (in a spacecraft).

Re: Moon escaping