|MadSci Network: Physics|
Well, you posed your question in an interesting way. I believe another scientist originally attempted to answer your question, since you referred to a previous question where clarification was required. With the information you supplied to me, I see a very clear answer. One of my backgrounds is in nuclear physics and radiation sciences and one of the simplest ways to produce an electron is through a process which is called "Pair Production". If this term is new to you, I will explain. Pair production is a process by which a photon creates an electron and a positron. So this process will yield both an electron and positively charged electron called the positron. The energy of the photon going into the interaction is equal to the sum of the two rest masses of the particles (E=MC^2) and the energies of both. This process requires the presence of a massive atom for the purpose of momentum conservation. The recoil energy of this massive atom is negligible compared to the terms of the above equation. Since we require a minimum of 2mc^2 for the products, we thus have the threshold energy required for this process wjich is 1.022 MeV. Practically speaking, we could perform this process by using an accelerator and focusing a highly collimated beam of monoenergetic photons on a given slab of material. Pair production is a process which becomes dominant over the other processes of interaction such as compton scattering and the photoelectric effect at energies in excess of 5 MeV. The downside of this method for producing an electron is that we have essentially formed a pair made up of an electron and a positron which can interact to form positronium, which after an extremely short lifetime, annihilates and two photons are created, which move in opposite direction to each other. I apologize that this probably did not reach you in time, but I answered it as soon as I was able. If you need further information you need only consult the subject of pair production, positronium, or pair annihilation. I hope this answered your question and if clarification is still needed just write us back and we will try to get you the answer you need.
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