Date: Tue Mar 9 10:55:17 1999
Posted By: Avra Brahma, Grad student, Aerospace Engineering, OSU
Area of science: Physics
ID: 913133970.Ph
Message:
let's find it's velocity at the bottom
v= sqrt(2*a*s) assuming it was dropped
= sqrt(2*9.8*381)
= 87.29 m/s
= 314 km/h
it's momentum is not much....around .9 kgm/s, not enough to knock you over
but, if it is sharp and comes into contact with a bare piece of skin it
might cause some damage.
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