|MadSci Network: Physics|
As far as I have been able to determine, the volume of an electron has not been determined. One might be able to deduce the volume of an electron from the effective radius of the Bohr hydrogen atom of 0.53 A or 0.53 x 1E -10 meters. Since the hydrogen atom is made up of one proton and one electron, one could assume a uniform density of subatomic particles throughout the volume (for argument's sake) where, density (H atom) = (1.0079 AMU)/[(4/3)*PI*(0.53e-10 m)^3] density (H atom) = 1.62 e30 AMU/m^3 Assume density (H atom) = density (e-), then density (e-) = (5.49 e-4 AMU)/ e- Volume and substituting and solving for the e- Volume, we find e- Volume = (5.49 e-4 AMU)/(1.62 e30 AMU/m^3) e- Volume = 3.4 e-34 m^3 or about 1800 times smaller than the volume of the Bohr hydrogen atom which is consistent with the mass differences between the proton and the electron. Dependant upon your assumptions, the same process could be used for other subatomic particles. However, due to the homogenizations involved, those calculations would also be plagued by the same inaccuracies. My best guess. 'Hope this helps! v/r Michael [Moderator note: Another approach is to equate the rest mass of the electron with the energy of a spherical distribution of an amount of charge equal to that of the electron. Doing this allows you to solve for the radius of the distribution.]
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