MadSci Network: Chemistry |
I am testing the basicity of no-lye and super strength hair texturizer cream developer. In order to do this, I mixed 3g of the cream developer solution in 200mls of distilled water and titrated the solution with 0.0993M HCl. Each solution had 0.05g of substance reacting with the acid. I would like to think that only the base, NaOH in Super strength, and LiOH in No-Lye solution, was reacting with the acid to give the 0.05g. However, cetyl alcohol, stearyl alcohol, cetearyl alcohol, and cetearyl phosphate, and propylene glycol also existed in the cream developer solution. Primary and tertiary alcohols react with HCl in SN1 reactions. I'm worried that interferring SN1 reactions occurred. Or is it safe to say that the strong bases were much more reactive with the HCl and the alcohols did not react. Another source also told me that as long as none of the alcohols were not tertiary, none of them reacted because tertiary alcohols are the most reactive via SN1 with HCl.
Re: How do I test basicity of no-lye & hair texturizer cream?
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