MadSci Network: Chemistry |
Nitrate ion (NO3-) is always a base--just an extremely weak one in an aqueous envrionment. In the Bronsted acid/base definition, nitric acid is a proton donor and nitrate ion is a proton acceptor.
HNO3 + H2O <===> H3O+
+ NO3- Ka = -1.4
(reference: Chemist's Companion)
Thus, nitrate can be considered an extremely weak base in water:
NO3- + H2O <===> H3O+ + OH- (Kb = 15.6)
Since water is a stronger base:
H20 + H2O <===> H3O+ + OH- (Kw = 14.0)
in water, nitrate is considered a non-base.
In an aprotic solvent (one with no readily ionizable hydrogens or protons), nitrate can acts as a base because it has electron pairs to donate to an electron pair acceptor. (The Lewis definition of acids and bases.)
Most aprotic solvents are non-polar (e.g. hydrocarbons), but to dissolve an ionic salt such as a nitrate, you need a polar solvent, hence N2O4.
N2O4 exists in equilibrium with NO2 and has a boiling point of 21 oC. (reference: Merck Index, 11th Ed., #6524) My inorganic chemistry is rusty from years of disuse, so I consulted "Advanced Inorganic Chemistry" (Cotton and Wilkinson, 3rd Ed.), which mentions that N2O4 is widely used as a solvent, but doesn't go into a great deal of detail.
Hope this helps!
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