MadSci Network: Chemistry |
According to my data from http://edie.cprost.sfu.ca/%7Erhlogan/electchm.html It is shown that for the two half-reactions: 2Fe(2+) --> 2Fe(3+) + 2e(-) Ered = -0.77 eV ClO(-) + H2O + 2e(-) --> Cl(-) + OH (-) Eox = +0.90 eV Ecell = Ered + Eox = -0.77 + 0.90 = +0.13 eV deltaG = -n.F.Ecell if deltaG < 0 the reaction occurs spontaneous under standard conditions. Because in this case deltaG = -2.96'500.0.13 = -25 J it is expected that this reaction occurs spontaneously and therefore CaOCl reacts with Fe(II)SO4 Sincerely, J. van der Rijt, MSc
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