MadSci Network: Chemistry
Query:

Re: VRD - electrolysis of sodium chloride

Date: Thu Jun 29 18:27:38 2000
Posted By: Dr. Michael Gallagher, Senior Research Chemist
Area of science: Chemistry
ID: 961456826.Ch
Message:

Ditiro,

It sounds like you read the answer I posted for : 946856031.Ch. The real answer is somewhat complicated, but here goes: There are three major reasons that a cell requires more voltage than the value calculated by the Nernst equation. These are

  1. Ohmic Potential, that is simply the finite resistance of a cell.
  2. Concentration Polarization, where the ions produced cannot diffuse away from the electrode at high enough rate. i.e. buildup
  3. Overpotential. Also known as Kinetic Polarization. This is the big one for production of Oxygen. This phenomena has to do with the rate at which you drive the reaction. If you want to produce large volumes of Oxygen gas, you will need to apply on the order of 1.5 to 2 volts in excess of the 1.229 Volts listed as a standard reduction potential. Overpotential is dependent upon the current density (amperes per square meter) and the metal that the electrode is composed of. Evolution of Hydrogen and Oxygen are particularly problematic as concerned with overpotentials. The amount of excess voltage required decreases with increasing temperature of the cell. The best metal to use is platinized platinum, that is fine deposits of platinum on a conductor comprised of platinum.

    Chloride ion in solution will become oxidized at a potential of 1.359 volts, thus if the overvoltage for the electrode of choice is large, then the chloride ions will be predominantly oxidized. Now as we lower the concentration of chloride ions, there are less of them to react at the surface, permitting some of the water to be decomposed into oxygen gas. Remember that overvoltage is not absolute. Small amounts of oxygen are being produced, but no evolution of bubbles is evident. As far as the actual concentration necessary to generate oxygen gas, that is going to depend on the specifics of the cell. i.e. applied voltage, electrode material and area, volume, stirring, temperature, etc., and I cannot give you a definitive answer.

    If you wish to generate oxygen at relatively large rates, or to demonstrate the 2 to 1 ratio of the composition of water, then you need to change electrolytes to something that does not oxidize at the anode, leaving only water to decompose into oxygen and hydrogen gases. Sulfuric acid fits that bill nicely. A few drops is all that is required, but a higher concentration will make the Ohmic Potential drop

    Any textbook on quantitative analysis would be a marvelous reference for a description of electrochemical cells and techniques. Keywords to look under are the terms described above, plus electrolysis and electrogravimetry,

    A good question!

    Michael M. Gallagher Ph.D.
    Senior Research Chemist
    J.R. Simplot Co.


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