Date: Fri Nov 10 10:49:23 2000
Posted By: Steve Taylor, Professional Engineer
Area of science: Engineering
ID: 971424954.Eg
Message:
Easy, and a grad student can't work this out ???
For a capacitor charge Q= capacitance C times voltage between the plates V
Q=CV
Let F be the frequency of the switch. I is current.
Then if charge Q flows in time 1/f then I (dq/dt) = fxCxV
And to a first approximation, since i/v= z then z=1/fc
Steve
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