Re: What is the gravity of Windsor?

What is the gravity of Windsor?

If one wants to determine the vertical gravity acceleration somewhere,
a precise measurement has to be done using a gravity meter (gravimeter),
that, nowadays, can give an accuracy better than 10^-8 Gal.
( NOTE: 10^-8 means 10 to the minus 8 power; I donīt have how to
express the numbers in this answer in another way, sorry)

1 mGal is 10^-3 Gal, a unit of gravity acceleration, given in honor
to Galileu. 1 Gal = 1 cm / s^-2 (1 cm per second squared)

If you don't have how to make a measurement, you can calculate
the theoretical gravity,
that can be used in some simple calculations (I don't know what is
the application you need the value to), by using the international
gravity formula, that states

g = ge * {1 + b1 * [sin (lat)]^2 + b2 * [sin (lat)]^4 + b3 * [sin(lat)]^6} 
  where

lat is the geographical latitude of the location
sin (lat) is the sine of the latitude
ge is the gravity at equator
b1,b2,b3 are adjusted coefficients

The value of the coefficients are

ge = 978.0327 Gal
b1 = 0.0052790414
b2 = 0.0000232718
b3 = 0.0000001262

and g is expressed in Gal (cm/s^2).

You can put the value of your latitude in formula and calculate
the gravity acceleration by this formula. Please be careful to
calculate the sin (lat), because the calculation of sine in most   
spreadsheets and calculators assumes the value of (lat) in radians.

Best regards

Eder C. Molina