All over the internet and more recently, on 2 books co-authored by the same physicist (Robert Resnick; _Quantum Physics_ and _Fundamentals of Physics Extended_) I've seen the standard form of the Heisenberg principle be expressed in the 2 following ways: delta_x * delta_p >= h-bar delta_x * delta_p >= h-bar/2 Is there a correct one or both are right, one being simply stricter than the other in some situation? In any case, what is the reason for this disparity? Thanks, Flavio
Re: What's the correct form of Heisenberg's uncertaint
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