MadSci Network: General Biology |
Daniel: I think this is a great question. You have a hypothesis, a question and have decided to test it. I did some horseradish peroxidase experiments when I was younger, (A different enzyme that catalyzes the same reaction). Actually, I do not think I can answer your question with the information you have given me. In enzymology, which is the study of enzymes, it turns out that just knowing which enzyme produces more of substance/product X is not indicitive of quantity, especially when we don't control for time. If one enzyme, say bird was 100 times as active but there was 100 times less, your experiment would still show that it had the same amount, which is clearly not true. I really like the fact that you repeated each experiment five times, but we also need to know what all five numbers were. Is the result you gave me an average? We also need to know your error, as well as the standard deviation for your data. For example, if the numbers for lamb and bird vary around 26 and 24cc, those are probably in fact the same number, and there is no difference between lamb and bird. If your values vary widely, it might be possible within your ability to measure the enzyme, there is no difference bewteen any of them. The next factor you did not tell me about was time, and this relates to how efficient one enzyme might be over another at converting peroxide H2O2 to water and oxygen. Did you let all of them react for the same amount of time, or until you saw no more bubbles, or how? If you let all of them go until completion, which is when the enzyme ceased to function, or you ran out of peroxide for example, then we can essentially compare one volume of oxygen to another as a means of relatively quantitating. If they all went for 2 minutes, and some were still bubbling that doesn't necessarily measure amount of catalase, but rather a combination of how much catalase and how good it is. We usually speak of enzymatic activity in terms of units of substrate per unit time... In this case you could say Lamb liver produced 2.6cm3 oxygen per minute. The third variable is enzyme conditions. Enzymes are extremely pH and temperature dependant, since they are proteins. Most enzymes are most active at the normal temperature of the host, so it is possible that the fish enzyme was performing out of it's range, and was therefore less active than it 'should be.' It is a good idea to keep temerpature constant when doing these experiments. And finally, I think your thoughts on why these results exist are good. Actually, the great part of doing experiments is that there are no wrong answers. Knowing that all three might contain the same amount of catalase is pretty neat too. In truth, I would guess the warm-blooded animals might have more catalase since their metabolisms would tend to produce more reactive oxygen species (Like hydrogen peroxide) requiring catalase. Whew, that was a mouthful. I hope it helps. -Matt-
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