| MadSci Network: Physics |
To answer your question, let's start with a couple of definitions. Voltage is "potential energy per unit charge". It is also commonly referred to as "potential difference". If you had an arbitrary collection of discrete charges at points P_1, P_2, etc., you would find the voltage at a point, P_0, by dividing the amount of charge at each of the other points by the distance from each point to P_0, then summing all these up. In this equation, amount charge is in the numerator and distance is in the denominator. You can create a large voltage either by having a lot of charge, or a little charge but packing it close together without allowing the charge to flow (no current). As you mentioned in your question, current is the flow of electrons: the more electrons flowing past a point at a given time, the higher the current. You can only have a high current if you have a large source of electrons. In the case of a battery, electrons are freed up as a consequence of an electro-chemical reaction. The voltage is a function of the chemistry used, the current is a function of reaction rate (and size). There are lots of electrons available inside the battery, it becomes a question of how fast they can be made usable by the chemical reaction. In the case of the ionizer, you used a very important term; "open circuit". This is the voltage when there is no current. One often uses a voltmeter to measure voltage. This instrument is designed to make this measurement while allowing very few electrons to flow. This is important because you want to make your measurement without the meter affecting what you are measuring. To illustrate this, let's go back to the battery. Let's say you found a battery and wanted to know if it was still good. You measured it with your voltmeter and got 1.5V. Now, you put it in your flashlight, but get only a weak glow. If you measured the voltage of the battery in the circuit, you would find it was significantly less. The battery had the "potential" to generate 1.5V, but the chemical reaction was exhausted, and could not supply the current necessary to keep the bulb lit.
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