MadSci Network: Physics
Query:

Re: does uv light pass through water?

Date: Thu Sep 4 16:15:03 2003
Posted By: Phil Marsden, Post-doc/Fellow
Area of science: Physics
ID: 1058307064.Ph
Message:

This question is a mixture of all sciences I suppose, but I will attempt to answer it from a physics point of view (since that is the bit I can be sure of). The simple answer to your question is actually quite easily found if you have access to a good library. However, it is not quite so easy of the absorption spectrum of pure water in the ultra violet region on the internet. It seems that this information is kept hidden away in journals. See for example: T.I.Quickenden and J.A.Irvin. "The ultraviolet absorption spectrum of liquid water" in Journal of Chemical Physics, Vol.72, No.8, pp 4416 (1980). and R.M.Pope and E.S.Fry. "Absorption spectrum (380-700nm) of pure water. II. Integrating cavity measurements" in Applied Optics, Vol.36, No.33, pp 8710 (1997). There is, however, quite a lot of data on the infra-red and microwave absorption of water which probably stems from interest in atmospheric sensing and LIDAR (laser RADAR). (Use these as search terms in your favourite search engine.) However, one good reference that I did find was the following: http://www.lsbu.ac.uk/water/ vibrat.html Which will also give you a much better idea of why water has the absorptions that it does. However, that wasn't the question right now. The data on this page does show, however, that on the red-side of the UV band the absorption of light is actually much less than in the visible spectrum. However, it can also be seen then that the absorption rises sharply as the UV wavelength gets shorter. What we need now are some points of reference. The following article gives us a useful definition of the ultraviolet region of the visible spectrum. http:/ /uvb.nrel.colostate.edu/UVB/publications/uvb_primer.pdf From this we get the following: UVC 100 to 290nm UVB 290 to 320nm UVA 320 to 400nm Now, if we then refer to (fairly random, but with an amusing name) tanning site: http://www.fabuloustan.com/uv lite.html We see that it is the UVA light that is primarily responsible for the darkening of the pigment in the skin and the UVB is responsible for the burning effect. However, we are also told that UVB has beneficial properties like producing vitamin D3 and melanin. Oh, and the UVC doesn't pass through the ozone layer, but you probably already knew this since this is why we are so worried about the hole in the ozone layer. So now, let us get back to the possibility of getting tanned underwater. Well, either from the graph at www.lsbu.ac.uk or data from the two articles that I mentioned above we can see that the light absorption (often given the label alpha) has the following values (where the units are "per metre"). Format: [wavelength] [absorption, alpha] [type of radiation] From the first article: 196 1.26 UVC 200 0.324 UVC 290 0.0163 UVC 305 0.0112 UVB 320 0.010 UVB From the second article: 380 0.011 UVA 400 0.0066 UVA This is an exponential scale so what this means is that if you multiply the absorption by the depth of water you are considering and then then raise the number e to minus the value you just worked out you will get the fraction of light that will reach you from the surface. Mathematically: A = e^(-alpha*d) where e is 2.71828182845905 and alpha is the absorption factor. So if you were swimming at a depth of 1m in pure water and wanted a tan (we can consider the worst case of light with a wavelength of 380nm) there would be an absorption of 1%. So this answers the question - not much of this light is absorbed. HOWEVER, there are other things to be taken into account. Firstly, there is a reflection loss at the surface of the water (a Fresnel loss). However, for a flat surface normal to the incoming light, this is actually only about 8%. Water is sadly, rarely flat though so there will be some extra scattering and reflection loss. You may have noticed that I have been very specific talking only about "pure" water. Unfortunately, few of us get the luxury of swimming in distilled water. Sea, lake and swimming pool water contains a million and one other things. Usually in the form of something living (although hopefully not in the latter!). Dissolved salts, algae, sand, mud, insects and a whole heap of other things are likely to be the problem more than anything else. This answer is getting less scientific. If it were me and I was still worried about the problem I would do the experiment. The most fun way would be to build an underwater light sensor with a blue film filter. Preferably using low-voltage components! Good luck and let me know what you measure if you like this solution. You could also do the experiment in the lab, but you would be unlikely to get the same water condition since the water would be still and particles would have time to settle. I hope this went someway to answer your question.


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