Subject: During electrolysis of H2O, what happens to the hydrogen at the anode?

I have been trying to understand the chemical reaction that takes place during 
the electrolysis of water.  My current understanding is as follows:
When an electrolyte such as an acid or salt is added to water, the covalent 
bond between H2O is replaced by an ionic bond between HO(-) H(+); which brings 
me to my first question: why does this happen?  
Secondly, at the cathode(-), this reaction takes place:
2OH(-) H(+)    +    2e(-)  -->   2H + 2OH(-) 
H + H --> H2 
	What happens to the 2OH(-)?
And last, at the anode(+), this reaction takes place:
4OH(-) H(+) --> 4HO + 4e(-) + 2H(+)
2HO + 2HO --> 2H2O2  
2H2O2 --> 2H2O + 2O
O + O --> O2
	My question is what happens the 2H(+) that is separated in the first 
step?
I hope you understand my questions; I tried to be as clear as I could.  Thank 
you for your time.

Re: During electrolysis of H2O, what happens to the hydrogen at the anode?