Subject: Exactly what is 'waving' at 90 degrees to an accelerating charge?

I understand that EM Waves are caused by accelerated charges. The EF and MF are 
at right angles to one-another and to the accelerated charges. If you would be 
so kind, explain to me the “rest of the story,” based on my beta-emitter 
example:  Let’s say an beta-minus particle is ejected from a Co-60 atom.  The 
remainder the nucleus reconfigures and recoils (accelerating the protons in the 
nucleus).  This acceleration of charges causes an EM waves (in this case, gamma 
rays of 1,130 and 1,333 keV) to be generated.  From this point on, I am 
confused.  How do these “accelerated protons” cause gamma radiation to be 
emitted?  “What” is moving at right angles to the motion of the charges?  Of 
course the answer is the E and M fields, which propogate outward. But why?  Is 
this correct: “There are charges -cat ions, anions, and electrons- all around 
space. These charges are attracting/repelling other charges. The accelerated 
protons (after beta-minus emission) cause a ‘disturbance’ in the electric fields 
of these space charges. This ‘ripple’ is an EM wave.” Is this similar to, say, 
squeezing part of a net together and seeing the whole net ripple when you let 
go?

Lastly, if EM waves are at 90 degrees from the accelerating charges, how does 
the sun’s rays sprout out toward us. How are the sun’s EM waves propogated 
toward us. Are the sun’s EM waves coming from accelerating charged particles, 
just as gamma rays from an beta-emitting nucleus?

Re: Exactly what is 'waving' at 90 degrees to an accelerating charge?