### Re: What heats water faster ? hotter/slower flow ? or faster/colder flow ?

Date: Fri Jun 18 17:12:37 2004
Posted By: Joseph Weeks, Engineer
Area of science: Physics
ID: 1087387936.Ph
Message:
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What a great question.  First, let's understand a thing or two about
solar panels.  Solar panels adsorb heat from the sun; the amount of
energy they adsorb is essentially fixed.  Therefore, for a certain sized
solar panel, your will only adsorb a specific number of calories, watts,
or BTUs.  The solar heat flux is roughly 1 kW/m2 (depending upon
elevation, how clear the air is, orientation of the solar collectors,
etc.), so each square meter of solar collector will produce roughly 1 kW
of heat for a portion of the day.  Whether your water runs fast or slow,
hot or cold, there is still only the 1kW of heat per square meter
available.  The essence of your question is how to get as much of that
1kW of heat into your pool as possible.  And that is entirely determined
by heat loss.

Heat loss is a function of temperature differences.  A pipe carrying hot
water will lose more heat to the surrounding air than a pipe carrying
cooler water.  A solar collector operating at high temperature will lose
more heat to the surroundings than one that is cooler.

Convective heat transfer is the movement of heat between a surface and a
surrounding fluid (like air).  The formula is Q=hA(T2-T1), where Q is the
amount of heat that is lost, h is the convective heat transfer
coefficient (typically 2 BTU/ft2hr, A is the area for heat transfer, and
T2 is the temperature of the hot surface, and T1 is the temperature of
air surrounding the surface.  Anything you can do to reduce h and A will
be useful in reducing Q, the heat loss.  However, it is clear that if T2
and T1 are close in temperature, you will lose less energy than if there
is a large difference.

You can insulate the pipes carrying your water, you can insulate the
solar collectors to decrease heat loss from the back.  There are a lot of
things that you can do to decrease heat loss.  The simple fact of the
matter is that more heat energy will be transferred to your pool by using
a higher, cooler flow than by using a slow, high temperature flow.
Higher flows, of course, require more pumping energy.  However, that
extra pumping energy also ends up as heat in your pool.

You can use the same heat loss equation to get a rough idea of how much
energy you are losing from your pool as a function of convective losses.
Even more significant, some of the water in your pool is evaporating,
taking about 540 BTUs of heat energy per pound that evaporates.  So,
perhaps one of the most effective things you can do to increase the
temperature of the pool is to cover it when you are not using it to
decrease evaporative losses.

Good luck with keeping your pool a bit warmer.

```

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