MadSci Network: Physics |
Before getting to the question, let me quickly suggest that you (and others) should avoid the term "STP" because not everybody uses it in the same way. Sometimes 0 degrees C is meant, sometimes (more often, I think) 25 degrees C. So people should always just state the T and P to remove all chance of confusion. On to this hypothetical question. What makes it non-trivial is the way water freezes (at least around normal atmospheric pressure), which is that the density gets lower (not higher as most things do when they freeze). But with a fixed volume, there is no place for the ice to "go". So one might think it would never freeze, at least not completely. But that would be wrong ... The constraint is that the overall density stays the same as it was at STP. Assuming that by STP you mean 25 degrees C, by the time you get down to the freezing point the liquid water will be more dense, leaving "room" for some ice. So quite soon you would get coexisting ice and liquid water near 0 degrees C, with the relative amounts of the phases determined by the constraint on the overall density. At the same time, the removal of more heat and freezing would cause the pressure to go up, compressing both the ice and the liquid water. At very high pressures, you could reach a state where the density of the ice was *higher* than the water you began with, so you could get it all frozen. A nice picture of the T/P boundaries for water and the various forms of ice is on this page: http://users.bigpond.n et.au/Nick/Mars/NH1.htm Unfortunately, I don't know a convenient place to point you for the densities of these phases. What I can tell you is that the minimum in freezing temperature, where the equilibrium ice phase becomes Ice III, is the point at which the ice structure becomes more dense than the coexisting liquid water, so at higher pressures the freezing behavior of water is "normal."
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