MadSci Network: Engineering |
Great question! The basic physical phenomenon behind ultrasonic transducers is something called "piezoelectricity" or "the piezoelectric effect". What happens is that certain crystals or ceramics generate a voltage when pressure is applied to them and they are compressed. Similarly, if you apply an electric voltage to the piezoelectric crystal, it will deform. A typical order-of-magnitude number (in english units) for this effect is 1 volt per 0.001 inch of compression. In other words, if you compress the right crystal by .001 inch, about 1 volt of electricity is generated. So now we have a handle on how ultrasonic transducers work; they work a lot like RADAR. In the first step, transmission, a high frequency electric voltage is applied to a piezoelectric crystal which causes it to deform rapidly and send out a pressure wave. Then the high frequency voltage is turned off, and you wait a few microseconds. The pressure waves that you've just sent out bounce off whatever is in their path and return back to the crystal. Here, the reflected pressure waves hit the crystal and generate an electric voltage. This voltage is sensed, processed by computer, and an image is generated. The key thing to making all this work is the piezoelectric effect. Hope this answers your question!
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