Re: converting tesla(magnetic flux density) into A m^2(magnetic dipole moment)

Hi, 

The unit of the magnetic dipole moment is Am^2in SI. The magnetic dipole 
moment can be written both a function of the B (magnetic flux density)and 
as a function of current 

            m=pi.r^2.l.B/uo  (Eq.1)

  where m magnetic dipole moment(Am^2in SI)
        r core radius
        l length of the torque rod
        i current
        B magnetic flux density(Tesla in SI)
        uo permeability of free space


  Question: V=r^2.l=1 cm^3=10^-6 m^3;
            B=1,23 tesla
            uo=1,2566.10^-6 N A^-2.
            m=?

  Substituting these values to Eq.1
           m=pi.(10^-6).1,23/(1,2566.10^-6)=3,074 Am^2.


Best wishes,