|MadSci Network: Engineering|
WE charge a horizontal flat ring of copper wire, center O, with excess electrons. When we rotate the ring about vertical axis thru O and BECAUSE it has resistance SOME of the electrons collide with the lattice. In contradistinction to this, if we send a current thru the wire the electrons diffusing past a fixed point are 1.6 10^18 per amp How does the B field of the moving charged ring compare to that of the stationary-with-current ring B1=B2 times what function of resistance?
Re: spinning a copper ring quite different to current in ring
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