MadSci Network: Physics |
I was looking at the spectrum of neutral Helium. Apparently Helium has two atomic states, which give rise to two non-mixable spectrums called the ortho and the para. In the para spectrum there is a sequence of transitions that involve the transition of electrons from the 1snp orbitals to the 1s2 ground state, which begins with the wavelength 584A. There is another which involves the transition of electrons from the 1snp orbitals to the 1s2s, n=2,3,4...- which begins with 20586A. The problem I have is that there is no wavelength associated with a 1s2s to 1s2 transition. I would assume that the shape of each is spherical, with the 2s being larger. The reason I am looking at this in detail is because I am interested in the accepted electron configuration model, and how it explains Helium. I find the idea that excited electron states involving the p orbitals have a choice of which state to 'fall' into. It is disconcerting that these two should be disconnected, where in theory an electron which makes a transition to a 2s needs to go back up before it can fall to the ground state. Perhaps, I am confused between the concepts presented in Bohrian terms, and those that are now generally accepted. Your insight would be appreciated. Thank you, Sean
Re: Why is there no wavelength associated with a 1s2s-1s2 in He I para spectrum
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