Re: cream of tartar + copper sulfate + H2O2 ----> ?

C4H4O62- (aq) + 5 H2O2 (aq)  ===> 4 CO2 (g) + 2 OH- (aq) + 6 H2O (l)

According to one source I found, the above equation represents the 
reaction between the tartrate dianion (C4H4...)with hydrogen peroxide.  
The gas formed is then CO2.  The reaction is catalyzed by the Cu+2 ion, 
so that is why nothing much happens until the copper sulfate solution is 
added.  Notice that the OH- ion is also formed.  That will tend to make 
the solution basic as the reation proceeds.  It is also well known that a 
solution of tartrate dianion with Cu+2 ion will react slowly when base is 
added.  In this reaction the Cu+2 oxidizes the tartrate, presumeably to 
CO2 and in the process the Cu+2 is reduced to Cu+1 ion which reacts with 
water (or oxygen) to produce Cu2O which is the red/orange precipitate.  
This reaction is accelerated by the heat from the other reaction.  The 
green solution could be from a small amount of Cu+1 ion that remains in 
solution.

It is also possible that the Cu+2 ion catalyzes the decomposition of some 
of the H2O2 to produce some oxygen as part of the gas.  I like the 
general tone of the experiment as an illustration of the law od the 
conservation of mass.  I wanted to get this off as an answer in a hurry.  
If you have more questions or I can be of more help contact me at 
jtfranzen@fuse.net

Dr. Jerry Franzen