Subject: Why is the work of the sodium-potassium pump secondary active transport?

In neurones, the active transport of Na+ ions out of the axon and K+ ions into the axon by the 
sodium-potassium pump is known as secondary active transport. I have read that secondary active 
transport involves one type of the 2 molecules moving along its electrochemical gradient with the 
other moving against its electrochemical gradient. I however always thought both Na+ ions and K+ 
ions moved against their electrochemical gradients during the restoration of the resting potential of a 
neurone after the action potential and hyperpolarisation have respectively occurred. I wonder: which 
type of ion, Na+ or K+, is it that moves against its electrochemical gradient during the restoration of 
the resting potential of a neurone if the work of the sodium-potassium pump does indeed involve 
secondary active transport that by definition does indeed involve one type of the 2 ions moving along 
its electrochemical gradient and one type moving against it? I also therefore wonder which of the 2 
types of ion moves along its electrochemical gradient? If it is, for example, the K+ ions that move 
against their electrochemical gradient, am I to then understand that during hyperpolarisation there 
are still more K+ ions inside the axon then outside even though the inside of the axon is very 
negative. If, for example, it is on the other hand the Na+ ions that move against their electrochemical 
gradient, am I then to understand that there are more Na+ ions outside the axon then inside even 
after the great influx of Na+ ions during the transmission of an action potential? Thank you very 
much - your help is greatly appreciated.

Re: Why is the work of the sodium-potassium pump secondary active transport?