Date: Fri Aug 8 14:27:35 2003
Posted By: Benjamin Monreal, Grad student, Physics, MIT
Area of science: Physics
ID: 1059729690.Ph
Message:
Hello Jagmeet,
An electron does not have minus infinity bare energy! Actually, nothing is
known to have negative energy - matter, antimatter, electromagnetic fields,
etc., always have positive energy or energy density. Something
straightforward like an electron - well, we can measure its mass, we can
measure its charge, and they are finite. If something in the mathematics
tells you that the mass is infinite ... well, it is the mathematicians who
need to fix it, because the electrons are not listening!
These sort of infinities do appear, and we have found ways to fix
them - in other words, we have uncovered mistakes or confusions in our
calculations. Let me explain a few of these infinities.
A quantum field theorist might try to draw a picture of a massless,
pointlike particle with charge e'. Based on the laws of quantum
electrodynamics, if you try to calculate the mass m'of this
particle, including the electromagnetic energy swarming tightly around it,
the answer appears to be infinity! But this infinity is just an anomaly of
the mathematics; if we start our calculation with e'
being infinitesimally small, and use it to generate the infinitely
large "self-energy" m', then the two infinities cancel
out! The actual mass-energy m, then, can be finite rather than
infinite (as
is observed) and the actual charge e can be finite rather than
infinitesimal, as is observed. You can read about this mathematical
trick, called "renormalization", at this
web page
There is also the "classical electron radius" issue. Based on the
(non-quantum) laws of electromagnetism, Maxwell's equations, you can
calculate the electromagnetic energy of a sphere of charge. This energy
sort of tells you how much work you must do to assemble a bunch of charges
in one place. If I give you ten electrons, and ask you to bring put them
into a 1-meter box together, you will have to do work - pushing on the
charges, since they are repelling one another - to get them all in the
box. If I ask you to put them into a 1-centimeter box, you'll have to push
even harder; even harder for a 1-micron box; etc. All of the work you do
ends up being stored inside of the box, in the electric fields. Anyway, if
you take this to the extreme - imagine trying to "build" a pointlike
electron, in a box of size zero, out of a handful of charged, pointlike
components - the energy
required would be infinite. This is essentially a classical analogue to
the quantum-field theory problem above. As a sort of solution, since the
electron is observed to
have a finite mass, we can sort of imagine it having a finite radius, just
so that this calculation works out. This is called the "classical electron
radius:. But
what this really tells us is that classical electrodynamics does not work
at really small scales. See the calculations here.
Maybe this has something in common with your "glue" idea?
Finally, there is always some confusion about "bare" versus "dressed"
particles in quantum field theory. Basically, when doing field theory
calculations - for example, you are calculating the probability that a
neutrino will collide with an electron - sometimes it is appropriate to use
something like e', the "bare charge", and sometimes it is
appropriate to use e, the physical charge (1.6 x 10^-19
Coulombs). The same is true for the mass. You see, sometimes your
calculations already include (in addition to whatever else you're
working on) that swarm of electromagnetic energy which is responsible for
the electron's mass; the calculation would be incorrect if you then
carelessly add in the electron's entire mass again. This is especially
important for quarks, for which you have to add up the electromagnetic
energy as well as the gluon fields. The "bare mass" of an up or down
quark, ignoring its gluon fields, is something like 5 MeV; put three of
them together, add up the gluons, and the mass is 1000 MeV! The difference
between "bare mass" and "dressed mass" is sort of like the difference
between entering 5 MeV, or 1000 MeV x (1/3), into your equations. (And,
the bare mass, I think, is always smaller than the dressed mass!)
Hope this helps,
-Ben
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