|MadSci Network: Physics|
As I've been taught & observed, the easiest pitch to hit a home run off of is low and inside. It would seem that a pitch farther from the fulcrum of the swinging bat would be easier to hit a home run on since the farther out on the bat that the ball makes contact, the more bat speed there is at that location on the bat, thus there's more force that the bat would be exerting on the ball when the two collide. Why is it that the center of the bat, where there's less motion on the part of the bat while swinging, results in a greater force being exerted on the ball?
Re: Why is low & inside the 'home run' pitch?
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