MadSci Network: Chemistry |
I understand your position. Here goes. Sample Equation: FeCl + NaPO4 ----> NaCl + FePO4 Step 1) Balance the oxidation numbers so that each coumpound has a net charge of zero. FeCl2 + Na3PO4 ----> NaCl + Fe3(PO4)2 Fe has an oxidation number of +2 and the chlorine has an oxidation # of -1, that's why you need two Cl to balance the one Fe. (-1x2=-2+2=0) Na's ox. # is +1, PO4 is a poly atomic ion that has a charge of -3. Step 2) Count the number of atoms of each type on both sides of the yield sign. Fe-1: Cl-2: Na-3: PO4-1: --> Fe-3: Cl-1: Na-1: PO4-2 Step 3) Add coefficients to the coumpounds to balance the atoms on both sides of the equations. 3FeCl2 + 2Na3PO4 ---> 6NaCl + Fe3(PO4)2 Step 4) Check to see if the numbers of atoms on both sides of the equation are equal. That's it! Some hints: 1) balance metals first, hydrogen and oxygen last. 2) If polyatomic ions remain together, count them as a single entity. 3) seperate the right and left side of the equation with a line drawn down vertically from the yield sign to seperate the two sides of the equation. 4) Keep track of the numbers of atoms every time you change a coefficient. Good Luck, Robert L. Judge
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