MadSci Network: Physics |
It has to do with symmetry. For a deuteron, j=1 and s=0 or 1. The states that correspond to these numbers are as follows: s=1 l=0 3S1 l=1 3P1 l=2 3D1 s=0 l=1 1P1 Of these states, 3S1 and 3D1 are even and the others are odd. Only the even states allow binding in the deuteron. Two neutrons (or two protons for that matter) cannot be in the even (symmetric) state because they are identical particles. For more information, consult Nuclear and Particle Physics by W.S.C. Williams, Section 9.8.
Try the links in the MadSci Library for more information on Physics.