| MadSci Network: Physics |
It has to do with symmetry. For a deuteron, j=1 and s=0 or 1. The states
that correspond to these numbers are as follows:
s=1 l=0 3S1
l=1 3P1
l=2 3D1
s=0 l=1 1P1
Of these states, 3S1 and 3D1 are even and the others are odd. Only the
even states allow binding in the deuteron. Two neutrons (or two protons
for that matter) cannot be in the even (symmetric) state because they are
identical particles.
For more information, consult Nuclear and Particle Physics by W.S.C.
Williams, Section 9.8.
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