Re: Is there a formula to calculate negative G force when a plane nose dive?

Hello There. Sorry about the delay in replying, but here is your answer
     Thinking about it logically, and from fundamentals, If a man of X kg 
(in your case 50 kg) is going to experience zero gravity, then the 
gravitational effect on the person will need to be equalled by the motion 
of the aircraft they are strapped to. Most simply the plane will need also 
to have a downward acceleration of 9.81 metres per second squared. This 
equation is simply Force = mass * gravitational acceleration. If the 
person were to experience negative g, then the plane would have to be 
experiencing a downward acceleration greater than the earths gravity. This 
is how they filmed Apollo 13 . The company used a large jumbo jet diving 
to create zero gravity. The most common equation used for acceleration is 
for circular motion. acceleration = (angular rotation)squared * radius. If 
the forces on an aircraft are gravity and the plane is also flying in a 
loop the loop fashion (and hence experiences also a centripetal 
acceleration), Then by summing the forces experienced by the aircraft in a 
vertical sense, the gravitational effect experienced by a person on the 
aircraft can simply be derived. To summarise, there is no specific/common 
equation used to derive the g-force on a person in a plane, but by summing 
the forces on the aircraft at any instantaneous moment, it can be 
determined. I hope I have answered your question. Guy