| MadSci Network: Microbiology |
Hi Judy -
There are a few possibilities for the result you saw. I'll give some explanation as to how you may arrive at an answer.
Each of the foodstuffs you mention contains different carbohydrates. When yeasts metabolize carbohydrates they release CO2 gas, which you then collect in the balloon.
Some possibilities to consider in your system:
To find content of specific sugars, try querying the Nutrient Lab Database at the USDA to detemrine grams of each kind of sugar in the foodstuffs. Select the option for "100 grams" when you enter queries of (1) honey, (2) maple syrup or (3) granulated sugar (same as table sugar). For the granulated sugar, you can also determine the main carbohydrate by looking on the label of most packaged sugars.
Carbohydrates have different formulae - the chemical formula for glucose is C6H12O6; that for maltose is C12H22O11. Which do you think weighs more, a molecule of glucose or a molecule of maltose? Expand this to the number of grams of each carbohydrate you have in your foodstuffs - it would be nice to know how many "molecules" of glucose, fructose, maltose or other sugars are present. To do this, you'll need to convert from the gram amounts to moles, a mole being 6.022 X 1023 molecules of a substance. So...
You can now assess the production of gas relative to the molarity of sugars in your solutions. If you vary these concentrations, what impact does it have on the gas produced? A simple way to do approach this question is to dilute each of your starting foodstuffs and add the same amount of the diluted material that you did for the undiluted material. What happens if you dilute your honey or maple syrup 5-fold and 10-fold (i.e., 1.0 milliliters (mL) of honey + 4mL of warm water, and 1mL of honey + 9 mL of warm water).
Some further questions you might investigate:
Lynn Bry, Moderator MadSci Network
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