MadSci Network: Physics |
Matt, I’m not going to mince any words and go right to the point of your question. The answer is because a full outer shell can provide the lowest level of electronic energy an atom can attain. There is quantum theory to explain this (and which you will hopefully learn in the future), but the important thing is this has been experimentally verified. That means a full outer shell can give an atom its most stable electronic configuration. Take a look at argon (Ar) on the periodic table: full outer shell, a “noble” gas, non-reactive except under extreme conditions. It’s stable in its lower energy configuration. It sees no reason to mess with it. (Matt, imagine if you will, you are on the couch with your Gameboy or Xbox; pizza and Coke on the coffee table. You are in your lowest energy configuration playing video games. Why would you want to get up and start walking back and forth through the house bumping into things?) But look at sodium (Na) and chlorine (Cl). Sodium has one less electron and chlorine has one more electron in their outer shells compared to argon. What is their situation? An atom of sodium has one 3s electron outside a closed shell, and it was experimentally found to take 5.14 eV (“electron volts”) of energy to remove that electron – its “ionization potential”. The chlorine, on the other hand, lacks one electron to fill a shell, and releases 3.62 eV when it acquires that electron – its “electorn affinity”. It takes only 1.52 eV of energy to donate the sodium 3s electron to chlorine when they are far apart, like infinity. When the atoms are brought closer together though, their electric potential energy becomes more and more negative, reaching -1.52 eV at about 0.94 nm separation. This means that if neutral sodium and chlorine atoms found themselves closer than 0.94 nm, it would be energetically favorable to transfer an electron from Na to Cl and form the “ionic bond”. So, this electron transfer leads to: (1) The formation of a sodium cation (Na+) and a chlorine anion (Cl-). (2) A dramatic and strong “electrostatic attraction” between them. (3) Full outer shells with lower energy for both of them. ---* Dr. Ken Beck
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