MadSci Network: Physics |
The two situations you propose are largely identical. Their ability to absorb gamma rays will depend strongly on the energy of the gamma rays. A 12 cm thick wall will certainly strongly absorb gammas with energies of 10's of kilo electron Volts (keV), but far more weakly attenuate gamma rays with energies of a few mega electron Volts (MeV). A detailed simulation will turn up minor differences based on geometry alone for various energies of gamma radiation, but generally gamma-ray transmission through a material is given by the exponential decay T = e(-u x). In this equation, T is the fraction tranmitted through a distance x in the material, e is the natural number (2.71828...), and u is a constant that depends on the gamma energy and material. To find u in the decay equation, consult the National Institute of Standards and Technology (NIST) website http://physics.nist.gov/PhysRefData/XrayMassCoef/tab4.html for a particular material. To get the actual value, use their value in (cm^2)/gram and multiply by the density of the material (see wikipedia for a particular material, they list many material properties) in g/cm^3, that gives you u in units of 1/cm. That means that when you multiply by x in centimeters you get a pure number which can be an exponent of e. That will help you compute T, the transmitted fraction, which is just the number (call it N) that pass through a particular material for a particular number (call it N_0) that hit the material. It turns out that by the properties of multiplying exponents, the number transmitted through 12 individual 1 cm thick slabs will be the same as the number transmitted through a single 12 cm thick slab. You can try it, a typical 1 MeV gamma ray has an attenuation coefficient of 0.06 cm^/g, and a density of 2.3 g/cm^3, giving a coefficient of .138/cm. Taking 1 individual slab gives you a transmission of 87% (0.87), 2 slabs is .87*.87 = .759, 12 of them gives you T = 0.191 or 19% transmission. A single 12-cm slab gives e^-1.656 = 0.191 as well.
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