| MadSci Network: Physics |
Your calculations are about right. What you calculated is called the color temperature. It's defined as the temperature of a blackbody that has the same spectrum as the body itself. A blackbody is a perfect radiator. A star comes pretty close to being a perfect radiator, I guess that's why you are doing this in astronomy class. The color temperature of a frosted 100 watt tungsten filament light bulb is at least 2100K, depending on manufacturer, operating voltage, frosting, etc. That means that a ball of gas in outer space, like a star, would have to be at a temperature of 2700K in order to radiate light similar to that of a 100 watt lightbulb. The temperature inside the lightbulb is tricky because we usually think of temperature as air temperature and light bulbs are evacuated to remove air. The tiny tungsten (actually, not pure tungsten) filament in the evacuated light bulb gets extremely hot, but doesn't burn up because there is no air. The filament is at least 2100K, but their is no transfer of heat until some of the radiation from the tungsten filament is absorbed by the glass of the light bulb as light passes through. Heating a filament by passing an electric current through in order to produce light is called incandescence. The color temperature of an electric stovetop as it glows orange-red, is about 675K, also due to incandescence. I love astronomy, I hope you continue learning about it!
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