MadSci Network: Other
Query:

Re: How many pennies fit on a chessboard if you doubled each square?

Date: Wed Apr 25 17:24:51 2001
Posted By: Michael Onken, Admin, MadSci Network
Area of science: Other
ID: 988225013.Ot
Message:

There are 64 (8 x 8) squares on a chessboard, and the first square has one penny, or 20 pennies, so, the number of pennies on any square would be 2 n-1 (where n is the number of the square). So the sum of all 64 squares worth of pennies would be written as:

There is a mathematical trick to solving this sum, which avoids a lot of calculations. If we start adding the pennies from the first few squares, we can begin to see a pattern:

1 + 2 = 3   for 2 squares
3 + 4 = 7   for 3 squares
7 + 8 = 15  for 4 squares
15+16 = 31  for 5 squares
31+32 = 63  for 6 squares
The pattern is that the sum of all previous squares is one less than the number of pennies in the next square, or the sum of the pennies on n number of squares is equal to one less than the number of pennies on the n+1 square, or the summation of a series of n doublings is equal to 2n - 1. So, for 64 doublings (chessboard squares), the sum (number of pennies) is 264 - 1, which is 18,446,744,073,709,551,615 pennies.


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