MadSci Network: General Biology |
Hi David, In response to your very good follow up question, let me clarify. The size of the letter IS NOT what subtends 1 minute of arc, it is the angular size of the gaps in the 20/20 size letter. For example, to differentiate a letter O from a letter G or C, we must be able to discern the gap which is several times smaller than the letter itself. Same for a letter P or letter F. A 20/20 letter has gaps that subtend 1 minute of arc but the letter itself is much bigger. Use the following equation: tan 0=x/distance For a target at 20 ft. or 6m: tan 0=z/20 feet or x/6m. And for a gap subtending 1 minute of arc: x=6(tan 0), x=6(0.000291), x= 0.001746m, x=1.746mm. For a letter at 20 feet, the gap height would be 1.746 mm and because there are 5 units in the letter E (count the 3 horizontal bars + 2 spaces), it would be 5(1.746mm)= 8.73 mm or 0.873cm. Convert to inches, you get approximately 0.873cm/2.54cm/inch= 0.344 inches. To get size of angular gap, 0.344 inches/5= 0.069 inches! I hope this helps! Kenton L. McWilliams, O.D. excerpts from: Primary Care Optometry 2nd edition TheodoreP. Grosvenor, OD, Phd Chapter 1, p.12
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