MadSci Network: Chemistry
Query:

Re: Why are the heaviest elements the least stable elements?

Date: Mon Mar 1 14:34:16 2004
Posted By: Bernadette Baca, Health Physicist, Division of Reactor Safety
Area of science: Chemistry
ID: 1076960188.Ch
Message:

There are basically two factors that affect the “stability” of larger 
atoms: ratio of the number of protons to neutrons and nucleus size.

First, the two basic forces in a nucleus are one of attraction and one 
repulsion.  Specifically, they are the "strong" nuclear force holding 
protons and neutrons together (binding energy) and the electrostatic force 
of protons repelling each other (Coulomb force).  Under certain 
arrangements (ratios) of protons and neutrons, the electrostatic forces 
balance each other and the binding energy holds the nucleus together.  
However, any other ratio of protons and neutrons where the electrostatic 
forces are not balanced, instability is created in the nucleus causing it 
to decay.  The atom will continue to decay until it reaches a stable 
combination of protons and neutrons.  Fundamentally, there are no stable 
nuclei with an atomic number (proton number) higher than 83 or a neutron 
number higher than 126.

Included in the factor of proton and neutron ratios is a concept of “magic 
numbers”.  These numbers are thought to be a geometric form of symmetry 
which create stability.  They include the following numbers: 2, 8, 20, 28, 
50, 82, 114, 126, 164.  These magic numbers are applied separately to the 
number of neutrons and protons.  This means a stable nucleus can have a 
neutron or proton number that is a magic number and the other not.  Nuclei 
that have an odd number ratio of protons and neutrons is not as stable as 
one that may have one odd and one even number protons or neutrons.  An 
even -even number of protons and neutrons is more stable than and even-odd 
ratio.  In addition, having a proton or neutron number that is a magic 
number makes those nuclei even more stable.  “Doubly magic” nuclei are 
extremely stable and have a combination of proton and neutron numbers that 
are both magic numbers; e.g. Helium has 2 protons and 2 neutrons, Oxygen 
has 8 protons and 8 neutrons and Lead has 82 protons and 126 neutrons.

Next, the nuclear forces keeping the atom’s nucleus together are strong 
but are short range forces.  The more protons in the nucleus, the more 
neutrons are needed for stability.  However, the nuclear forces holding 
everything together eventually become weak as the size of nucleus grows.  
Or in more complex words, a more strong nuclear force is needed to 
compensate for the increasing Coulomb repulsion (proton-proton repulsion) 
in larger nuclei.  This is the biggest factor in why the heaviest elements 
(atoms) are not as stable as smaller one.

I hope this may begin to answer your question.

For more information on nuclei stability and composition, you may want to 
look through the following websites: 
 http://207.10.97.102/chemzone/lessons/11nuclear/nuclear.htm
 http://www.2bengineer.net/chemistry/ch5_3_2.html
 http://www.infodotinc.com/doenuclearphys/nuclearphysics17.htm	
 http://hep.ucsd.edu/~branson/130/130b/130b_notes_prod/node128.html
 http://online.cctt.org/physicslab/content/PhyAPB/lessonnotes/dualnature/nuc
lear.asp
 http://www.phys.ufl.edu/~acosta/phy3101/lectures/nuke2.pdf
 http://particleadventure.org/particleadventure/


Two research papers providing a detailed look at nuclide stability through 
geometric symmetry may be found at: http://www.phy.hr/~npavin/science/power_lawsCSF.pdf
 http://www.blazelabs.com/f-p-swave.asp



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