MadSci Network: Chemistry |
The question that you have asked is extremely complicated due to a number of factors that will effect the relative solubility of Calcium Carbonate. The factors that will effect the solubility are: 1. Temperature (LeChatelier's Principle) 2. pH 3. Concentration of dissolved Carbon dioxide in the water. 4. Concentration of NaCl in the saline solution. The solubility product for Calcium carbonate and pure water at 20C is 5.0 X 10exp.-9. The solubility of Calcium carbonate in seawater at 20C is 6.0 X 10exp.-7. Both numbers illustrate that Calcium carbonate is not readily soluble in water. The solubility in seawater is also very low, but is 100X more soluble than pure water due to the effects of interionic attraction in aqueous media of high concentration. The possibility of Metathesis Reactions, in which cations (+) and anions (-) exchange partners also exsists. I am afraid that I do not have a "magic" formula for you to make the solubility determination, but an increased understanding of all the variables is a step in the right direction.
Try the links in the MadSci Library for more information on Chemistry.